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November 25, 2014

November 25, 2014

Posted by **Ryan** on Wednesday, November 9, 2011 at 11:37pm.

- calculus -
**Steve**, Thursday, November 10, 2011 at 4:37pmThe curves intersect at (-2,-1) and (-3/4,3/2)

So, we want to sum up the washers with inner radius r and outer radius R

Int pi*(R^2 - r^2)[-1,3/2] dy

where

R = y - y^2 + 4

r = y^2 - 3 + 4 = y^2 + 1

R^2 - r^2

= (y^2 - y^3 + 4y - y^3 + y^4 - 4y^2 + 4y - 4y^2 + 16) - (y^4 + 2y^2 + 1)

= -2y^3 - 9y^2 + 8y + 15

V = pi*(-1/2 y^4 - 3y^3 + 4y^2 + 15y)[-1,3/2]

= 1085pi/96

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