Thursday

April 24, 2014

April 24, 2014

Posted by **Ashley** on Wednesday, November 9, 2011 at 6:48pm.

- Calculus -
**Steve**, Wednesday, November 9, 2011 at 8:43pmIncreasing where f' > 0

Decreasing where f' < 0

f'(x) = 24x^2 + 4x^3 = 4x^2(6+x)

Concave up where f'' > 0

Concave down where f'' < 0

f'' = 48x - 12x^2 = 12x(4-x)

Max where f' = 0 and f'' < 0

Min where f' = 0 and f'' > 0

**Related Questions**

Calculus - Consider the function f(x) = x - lnx. Find the intervals on which f(x...

math - . Given the following function, f(x)=-x^2 -8x find: (a) vertex, (b) axis...

Calculus - Consider the function f(x)=-2x^3+33x^2-108x+2. For this function, ...

math-calc - Consider the function f(x)= (2x+8)/(6x+3). For this function there ...

calculus help please - Consider the function f(x)=2x+9x^–1.? For this function ...

Calculus - Consider the function f(x)=xe^2x. Find the intervals on which f(x) is...

Calculus - Consider the function f(x)=4(x-5)^(2/3). For this function, there are...

Calculus - Consider the function f(x)=4(x−3^2/3. For this function there ...

calculus - 2. Consider the function f defined by f(x)=(e^X)cosx with domain[0,...

calculus - 2. Consider the function f defined by f(x)=(e^X)cosx with domain[0,...