Posted by Jul on Wednesday, November 9, 2011 at 5:59pm.
To start the crate sliding down the incline, you must provide a force component in that direction that exceeds the maximum static friction force minus the weight component in that direction.
When the two forces are equal,
M g cos 19.5 * Us = M g sin 19.5 + 537 cos19.5
where Us is the static friction coefficient.
Solve for Us
could you clarify what M is? i know g is the gravity which will be 9.81 but im not sure about the M
Related Questions
physics - A 220-kg crate rests on a surface that is inclined above the ...
Physics - A crate of mass 50.0 kg rests on a flat surface, and there is a ...
physics - A crate is sliding down a ramp that is inclined at an angle of 55.4&...
Physics - A 19 kg crate is placed on an inclined ramp. When the angle the ramp ...
Physics - A man drags a 71.5-kg crate across the floor at a constant velocity by...
Physics - A 50 kg crate is initially at rest on a plane inclined at an angle of...
physics - A crate of mass m (=40 kg) is placed at rest on a (frictionless) ...
Physics - A 45 kg crate is placed on an inclined ramp. When the angle the ramp ...
Physics - A 32 kg crate is placed on an inclined ramp. When the angle the ramp ...
Physics - A 32 kg crate is placed on an inclined ramp. When the angle the ramp ...
For Further Reading
