if 1 adult male is randomly selected and is assumed to have 20 lb of carry on baggage, find the probabilty that his total is greater than 195 lb
More data needed. What is the mean and standard deviation of the baggage weights? Is 195 a typo?
To find the probability that the total weight of a randomly selected adult male's carry-on baggage is greater than 195 lb, we need to know the distribution of weights carried by adult males. Without that information, we cannot calculate an exact probability.
However, assuming that the weights are normally distributed, we can use the mean and standard deviation to approximate the probability. Let's say the mean weight carried by adult males is μ and the standard deviation is σ.
To approach this, we need to standardize the total weight by converting it into a standard score, or z-score.
The formula for calculating the z-score is:
z = (x - μ) / σ
In this case, we want to find the probability that the total weight is greater than 195 lb, which in terms of the z-score would be: P(z > (195 - μ) / σ).
However, since we don't know the mean and standard deviation, it is not possible to provide an exact answer without further information.