Posted by ali on .
A student measures 0.2452 g of a monoprotic solid acid, and dissolves the solid in water to make 100.0 mL of solution. the entire solution is titrated to a phenolphthalein endpoint with 45.06mL of 0.1725M KOH.
A. what is the molarity of the acid solution?
B. what is the molar mass of the solid acid?
moles KOH = M KOH x L KOH = ?
moles unknown acid = moles KOH since the acid is monoprotic.
moles acid = grams/molar mass
Solve for molar mass.