Thursday

November 20, 2014

November 20, 2014

Posted by **HM** on Wednesday, November 9, 2011 at 4:24pm.

Could someone help me with how to do this?

- PROBABILITY MATH -
**bobpursley**, Wednesday, November 9, 2011 at 4:40pmPr(zero men)=4/7*3/6=12/42

pr (one man)=3/7*4/6+4/7*3/6=24/42

Pr(two men)= 3/7*2/6= 6/42

Now if you mean by "expected" value, then one man is expected.

**Answer this Question**

**Related Questions**

PROBABILITY MATH - From a group of 3 men and 4 women, a delegation of 2 is ...

math correction - can someone correct this problem for me thanks A group of 7 ...

math - In a group of 7 men and 8 women, how many committees of 5 can be selected...

gr12 math - froma group of 6 ladies and 4 men, determine in how many ways a ...

math - from a group of women and 4 men, determine in how many ways a committee ...

math, bobpursley - so how did you say to do part c c) if there is 2 woman and 5 ...

Probability - This is an example question, but I'm not sure how my instructor ...

math - a committee of 5 people is to be selected from a group of 6 men and 9 ...

maths - .A committee of 6 is to be selected from a group of 6 men and 9 women. ...

math - a class consists of 14 men and 16 women. A group of 5 is randomly chosen ...