PROBABILITY MATH
posted by HM .
From a group of 3 men and 4 women, a delegation of 2 is selected at random. What is the expected number of men in the delegation? Round your answers to two decimal places as needed.
Could someone help me with how to do this?

Pr(zero men)=4/7*3/6=12/42
pr (one man)=3/7*4/6+4/7*3/6=24/42
Pr(two men)= 3/7*2/6= 6/42
Now if you mean by "expected" value, then one man is expected.