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September 22, 2014

September 22, 2014

Posted by **HM** on Wednesday, November 9, 2011 at 4:24pm.

Could someone help me with how to do this?

- PROBABILITY MATH -
**bobpursley**, Wednesday, November 9, 2011 at 4:40pmPr(zero men)=4/7*3/6=12/42

pr (one man)=3/7*4/6+4/7*3/6=24/42

Pr(two men)= 3/7*2/6= 6/42

Now if you mean by "expected" value, then one man is expected.

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