A kindergarten school has square mats in two colors, red and blue. The ratio of the perimeter of the red mat to the perimeter of the blue mat is 1 : 2. The area of the red mat is blue mat is 9 square feet.
What is the area of the red mat?
S = sqrt9 = 3 Ft. = Length of a side of blue mat.
Pb = 4 * 3 = 12 Ft. = Perimeter of blue mat.
Pr/Pb = 1/2,
Pr/12 = 1/2,
Pr = 6 Ft.
4S = 6,
S = 1.5 Ft. = Length of a side of red mat.
Ar = S^2 = (1.5)^2 = 2.25 sq. Ft. = Area of red mat.
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To find the area of the red mat, we first need to find its side length.
Let's assume the side length of the red mat is "x" feet. Then the perimeter of the red mat would be 4 times the side length.
So, the perimeter of the red mat is 4x.
Given the ratio of the perimeter of the red mat to the perimeter of the blue mat is 1:2, we can set up the following equation:
(4x) / (2x) = 1/2
To solve for x, we can cross multiply:
2(4x) = 1(2x)
8x = 2x
Subtracting 2x from both sides, we get:
6x = 0
x = 0
However, since we cannot have a mat with zero side length, we should conclude that this scenario is not possible.
Therefore, the problem statement must be incorrect or there might be some missing information needed to solve the problem correctly.