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April 20, 2014

April 20, 2014

Posted by **Courtney** on Wednesday, November 9, 2011 at 1:43pm.

- calculus -
**Steve**, Wednesday, November 9, 2011 at 7:56pmWe want

Int(x dy)[0,b] = Int(x dy)[b,9]

x = 1/4 y^(1/2)

Int(y^(1/2))[0,b] = Int(y^1/2)[b,9]

2/3 y^(3/2)[0,b] = 2/3 y^(3/2)[b,9]

2/3 b^(3/2) = 2/3 9^(3/2) - 2/3 b^(3/2)

4/3 b^(3/2) = 2/3 9^(3/2)

2b^(3/2) = 9^(3/2)

2^(2/3) b = 9

b = 9/2^(2/3) = 9/cbrt(4)

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