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December 26, 2014

Homework Help: Organic Chem

Posted by Bryan on Wednesday, November 9, 2011 at 2:50am.

The following reaction is a single-step, bimolecular reaction:

CH3Br + NaOH ---> CH3OH + NaBr

When the concentrations of CH3Br and NaOH are both 0.150 M, the rate of the reaction is 0.0090 M/s.

a) what is the rate of the reaction if the concentration of CH3Br is doubled?
______ M/s

b) What is the rate of the reaction if the concentration of NaOH is halved?
______ M/s

c) What is the rate of the reaction if the concentrations of CH3Br and NaOH are both increased by a factor of five?
______ M/s


Please help! I have no idea how to start this problem off!

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