# algebra3

posted by
**Joe**
.

Why isn't the absolute value inequality (x^2-1)</=8 set up as -8<x^2-1<8 yielding -7<x^2<9 so +/-sqrt-7<x<+/-sqrt9 so +/-isqrt7<x<+/-3?

posted by
**Joe**
.

Why isn't the absolute value inequality (x^2-1)</=8 set up as -8<x^2-1<8 yielding -7<x^2<9 so +/-sqrt-7<x<+/-sqrt9 so +/-isqrt7<x<+/-3?