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solve (x+17)(x-6)(x+14)>0

  • algebra - ,

    y = (x+17)(x-6)(x+14)
    this cubic would have x-intercepts at
    x = -17, -14, and 6
    its first term is x^3, so it would rise in the 1st quadrant.
    So the curve is above the x-axis, or positive for

    -17 < x < -14 or x > 6

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