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April 24, 2014

April 24, 2014

Posted by **Bill** on Tuesday, November 8, 2011 at 8:23pm.

- algebra -
**Reiny**, Tuesday, November 8, 2011 at 8:44pmconsider

y = (x+17)(x-6)(x+14)

this cubic would have x-intercepts at

x = -17, -14, and 6

its first term is x^3, so it would rise in the 1st quadrant.

So the curve is above the x-axis, or positive for

-17 < x < -14 or x > 6

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