A ball rolls along a desktop with an uniform velocity of 3 m/s. What is the displacement after 10 seconds have passed?

A ball is thrown upward with an initial velocity of 18 m/s? What is the maximum height the ball reaches if the ball is assumed to leave from the ground?


A ball is dropped from a 35 m tall building. The ball takes how long to impact the ground?

(a) A ball rolls along a desktop with an uniform velocity of 3 m/s. What is the displacement after 10 seconds have passed?

D = V*t

(b) A ball is thrown upward with an initial velocity of 18 m/s?
Vo^2/2 = g H
Solve for height, H

(c) A ball is dropped from a 35 m tall building. The ball takes how long to impact the ground
35 = (g/2) t^2
Solve for time, t.

To find the displacement, maximum height, and time taken for the given situations, we can use basic equations of motion. Let's break down each question and find the answers step by step:

1. The ball rolling along a desktop:
The velocity of the ball is given as 3 m/s, and the time is given as 10 seconds. We can use the formula: displacement = velocity × time.

Therefore, the displacement = 3 m/s × 10 s = 30 m.

So, the ball's displacement after 10 seconds is 30 meters.

2. The ball thrown upward:
The initial velocity of the ball is 18 m/s. We need to find the maximum height reached. We can use the formula: time taken to reach maximum height = (final velocity - initial velocity) / acceleration.

Since the ball is assumed to leave from the ground, the final velocity at the maximum height will be zero. Therefore, we have:
time taken = (0 - 18 m/s) / (-9.8 m/s^2) = 18/9.8 s

Now, we can find the maximum height by using the formula: maximum height = initial velocity × time taken + 0.5 × acceleration × (time taken)^2.

maximum height = 18 m/s × (18/9.8 s) + 0.5 × (-9.8 m/s^2) × ((18/9.8 s)^2)

So, the maximum height the ball reaches is the calculated value using the above formula.

3. The ball dropped from a 35 m tall building:
The height of the building is given as 35 m. We need to find the time taken for the ball to impact the ground. We can use the formula: time taken = √(2 × height / acceleration).

First, we need to find the value of acceleration. In this case, acceleration due to gravity is appropriate, which is approximately 9.8 m/s^2.

time taken = √(2 × 35 m / 9.8 m/s^2)

So, the ball takes the calculated time to impact the ground.

Remember, when solving such physics problems, always consider the proper units and use appropriate formulas based on the given information.