Posted by **Ruth** on Tuesday, November 8, 2011 at 7:12pm.

1)What must be the orbital speed of a satellite in a circular orbit 740 above the surface of the earth?

2)What is the period of revolution of a satellite with mass that orbits the earth in a circular path of radius 8000 (about 1630 above the surface of the earth)?

- PHYSIC -
**drwls**, Tuesday, November 8, 2011 at 7:58pm
You must provide units with your numbers. You should have learned that by now

- PHYSIC -
**tchrwill**, Friday, November 11, 2011 at 5:11pm
Since 8000 - 1630 = 6370, the radius of the earth in km, I believe I am on safe ground assuming that you mean "740km" above the earth in your first question.

The velocity required to maintain a circular orbit derives from Vc = sqrt(µ/r) where Vc = the velocity in m/s, µ = the earth's gravitational constant, 3.9863x10^14 m^3/sc^2 and r = the orbital radius in meters.

Therefore,

Vc = sqrt[3.9863x10^14/(6370+740)1000]

The period of a particular orbit derives from

T = 2(Pi)sqrt(r^3/µ)

I'll let you complete this one.

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