If the resistance of each of the light bulbs is 6.0 ohms, what resistance does the battery see?
If the resistors are in series:
R = 6 + 6 = 12 ohms.
If they are in parallel:
R = (6*6) / (6+6) = 3 Ohms.
To find the total resistance that the battery sees in a circuit with light bulbs connected in parallel, you can use the formula:
1/RTotal = 1/R1 + 1/R2 + 1/R3 + ...
Where RTotal is the total resistance, and R1, R2, R3, etc. are the resistances of the individual light bulbs.
In this case, since all three light bulbs have the same resistance of 6.0 ohms, we can substitute the values into the formula:
1/RTotal = 1/6.0 + 1/6.0 + 1/6.0
Simplifying the equation:
1/RTotal = 3/6.0
To further simplify, we can convert 6.0 to 3.0:
1/RTotal = 3/3.0
1/RTotal = 1.0
To isolate RTotal, we take the reciprocal of both sides:
RTotal = 1/1.0
Therefore, the resistance that the battery sees in this circuit is 1.0 ohm.