Posted by victor on Tuesday, November 8, 2011 at 5:16pm.
the 2nd, 3rd, and 4th term of an arithemetic progression are x2, 5 and x+2 respectively, calculate the value of x and hence find the 20th term..

mercy land  Steve, Wednesday, November 9, 2011 at 12:12am
since these are consecutive terms, their difference is the same, so
5(x2) = (x+2)5
5x+2 = x+25
7x = x3
2x = 10
x = 5
So, the three terms are 3,5,7
So, Tn = 1+2(n1)
T20 = 1+2(19) = 39

new life  mercy, Tuesday, May 24, 2016 at 12:35am
3(19)=39 : 57=39 : 5739=18
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