Posted by **victor** on Tuesday, November 8, 2011 at 5:16pm.

the 2nd, 3rd, and 4th term of an arithemetic progression are x-2, 5 and x+2 respectively, calculate the value of x and hence find the 20th term..

- mercy land -
**Steve**, Wednesday, November 9, 2011 at 12:12am
since these are consecutive terms, their difference is the same, so

5-(x-2) = (x+2)-5

5-x+2 = x+2-5

7-x = x-3

2x = 10

x = 5

So, the three terms are 3,5,7

So, Tn = 1+2(n-1)

T20 = 1+2(19) = 39

- new life -
**mercy**, Tuesday, May 24, 2016 at 12:35am
3(19)=39 : 57=39 : 57-39=18

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