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Posted by **omg** on Tuesday, November 8, 2011 at 3:44am.

What is the gravitational force on an object of mass 4.8kg at the north pole of Neptune?What is the apparent weight of this same object at the Neptune's equator? (Note that Neptune’s “surface” is gaseous, not solid, so it is impossible to stand on it.)

- physics -
**drwls**, Tuesday, November 8, 2011 at 7:58amThe acceleration of gravity on the surface of Neptune is

g' = G M/R^2,

where M is the planet's mass.

M g' will be the weight registed at the poles. G is the universal constant of gravity

The "apparent weight" at the equator will be reduced from M g' by the centripetal force M R w^2, where w is the rotational angular velocity in radians/s), which you can deduce from the 16 hour length of a day.

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