Posted by **UG** on Tuesday, November 8, 2011 at 1:20am.

The amount of corn chips dispensed into a 16-ounce bag by the dispensing machine has been identified at

possessing a normal distribution with a mean of 16.5 ounces and a standard deviation of 0.1 ounce. Suppose 400

bags of chips were randomly selected from this dispensing machine. Find the probability that the sample mean

weight of these 400 bags exceeded 16.6 ounces

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**PsyDAG**, Tuesday, November 8, 2011 at 10:17am
Z = (mean1 - mean2)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

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**niel**, Wednesday, June 5, 2013 at 4:04pm
.5062

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**Anonymous**, Saturday, April 18, 2015 at 4:47pm
0.3085

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**Andrea**, Saturday, April 23, 2016 at 11:04am
Actually, I believe it's approximately zero.

Source: I have a MS in Mathematics

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**Andrea**, Saturday, April 23, 2016 at 11:06am
Pardon me... approximately zero if the standard deviation is 0.2 ozs.

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