Posted by Anonymous on .
The average score of all golfers for a particular course has a mean of 73 and a standard deviation of 3. Suppose
36 golfers played the course today. Find the probability that the average score of the 36 golfers exceeded 74.
Z = (mean1 - mean2)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.