Posted by JS on .
A 5 mL sample of an unknown liquid is placed into a 250 mL flask that has had all of the air removed. The pressure measured in the flask is found to be 39.9kPa. In a separate trial the student puts 214 mL of the same liquid into the same flask at the same temperature. What will the pressure measure (in kPa) in the second trial?
I did: (39.9kPa/5mL) * 214mL = 1707.72kPa
Is this correct?
In the first trial, was at least a drop of the liquid present when P was 39.9 kPa? If so then that is the vapor pressure of the liquid at that temperature and the pressure in the second trial will be 39.9 kPa.
Thank you. I just asked my tutor online for help, so I do not need any help anymore. Thank you anyways! :)