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March 30, 2017

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Please help me with the following 2 questions.

1. Find the area of the curved surface of a right-circular cone of radius 6 and height 4 by rotating the straight line segment from (0,0) to (6,4) about the y-axis.

2. Use the Maclaurin polynomial of degree 4 to approximate sin(0.2). The formula given is the sum between k = 0 and infinity of [-1^k]/(2k+1)!x^(2k+1). I tried using the following but got it wrong

0.2 - (0.2)^3/3! + (0.2)^5/5! - (0.2)^7/7! + (0.2)^9/9!.

Please help.
Thanks

  • Calculus - ,

    The area of a cone of radius r and slant height s is πrs

    r = 6
    s^2 = 6^2 + 4^2
    s = √52 = 2√13
    area = 12π√13


    For MacLaurin polynomials, I may be wrong, but I thought you wanted degree 4. That would just be

    0 + 1/1! x + 0/2! x^2 + -1/3! x^3 + 0/4! x^4
    = x - x^3/3!
    = .2 - .008/6 = 0.1987

  • Calculus - ,

    Thanks Steve.

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