Calculate the morality of the solution 0.450 mol of Na2S in 1.75 L of solution
I didn't know solutions at the opportunity to be immoral. :-).
I assume you meant to type molarity (and not molality).
M = moles/L soln.
what is the molarity of 0.450 mol of na2s in 1.65 l of solution
To calculate the molarity of a solution, you need to know two things: the amount of solute (in moles) and the volume of the solution (in liters).
In this case, you have 0.450 moles of Na2S and it is dissolved in 1.75 liters of solution.
The formula to calculate molarity (M) is as follows:
Molarity (M) = moles of solute / volume of solution (in liters)
Plugging the values into the formula:
Molarity (M) = 0.450 mol Na2S / 1.75 L
Now, let's calculate the value:
Molarity (M) = 0.257 M
Therefore, the molarity of the solution containing 0.450 mol of Na2S in 1.75 L of solution is 0.257 M.