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October 1, 2014

October 1, 2014

Posted by **jay** on Monday, November 7, 2011 at 7:58pm.

- calculus -
**bobpursley**, Monday, November 7, 2011 at 8:05pmIf it is even, P(x)=ax^4+bx^2+c

P(0)=10 so c is 10

p'=5ax^3+2bx=0

x(5ax^2+2b)=0

maximum at x=+-1

so 5ax^2=-2b

or 5a=-2b or a=-5/2 b

but P(1)=13=(-5/2 b)*1+ b(1)+10

or 3/2 b=10 b=20/3 and a=-5/2 * 20/3=100/6

check P(-1)=13

it checks.

- calculus -
**Jose**, Monday, November 7, 2011 at 9:00pmWhy do we end up with f(x) instead of f(t) on the Second Fundamental Theorem of Calculus?

- calculus -
**Anonymous**, Tuesday, April 1, 2014 at 8:19pm5x^2

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