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March 31, 2015

March 31, 2015

Posted by **Rachel** on Monday, November 7, 2011 at 7:24pm.

(tanX-secX)^2= 1-sinX/1+sinX

- Trig -
**declan**, Monday, November 7, 2011 at 7:42pm(sec x - tanx)^2 = (1-sinx)/(1+sinx)

use these substitutions

sin²(x) + cos²(x) = 1

cos²(x) = 1 - sin²(x)

(sec(x) - tan(x))²

=(1/cos(x) - sin(x)/cos(x))²

= (1-sin(x))² / cos²(x)

= (1-sin(x))² / (1 - sin²(x))

= (1-sin(x))² / [(1+sin(x))(1-sin(x))]

= (1-sin(x)) / (1+sin(x))

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