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August 1, 2014

August 1, 2014

Posted by **Mishaka** on Monday, November 7, 2011 at 6:12pm.

(x^1/2 cscx sinx).

- Calculus (Derivatives) -
**Steve**, Monday, November 7, 2011 at 8:14pmFirst off, csc * sin = 1

So, y = √x

However, if you insist on doing it the hard way

y = √x cscx sinx

y' = 1/2√x cscx sinx + √x(cscx sinx)'

= 1/2√x * 1 + √x(-cscx ctnx * sinx + cscx cosx)

= 1/2√x + √x(-ctnx + ctnx)

= 1/2√x

same answer

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