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March 27, 2017

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Find an equation of the tangent line to the curve at the given point.

y = sin(sin x), (pi, 0)

  • Calculus - ,

    Nothing simpler...

    y = sin(sin x)
    y' = cos(sin x)*cos x

    y'(pi) = cos(0)*cos(pi) = 1(-1) = -1

    so, you want the line through (pi,0) with slope = -1

    (y-0)/(x-pi) = -1
    y = pi - x

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