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November 29, 2014

November 29, 2014

Posted by **Nyke** on Monday, November 7, 2011 at 4:51pm.

y = sin(sin x), (pi, 0)

- Calculus -
**Steve**, Monday, November 7, 2011 at 7:11pmNothing simpler...

y = sin(sin x)

y' = cos(sin x)*cos x

y'(pi) = cos(0)*cos(pi) = 1(-1) = -1

so, you want the line through (pi,0) with slope = -1

(y-0)/(x-pi) = -1

y = pi - x

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