Posted by Nyke on .
Find an equation of the tangent line to the curve at the given point.
y = sin(sin x), (pi, 0)

Calculus 
Steve,
Nothing simpler...
y = sin(sin x)
y' = cos(sin x)*cos x
y'(pi) = cos(0)*cos(pi) = 1(1) = 1
so, you want the line through (pi,0) with slope = 1
(y0)/(xpi) = 1
y = pi  x