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October 1, 2014

October 1, 2014

Posted by **Adrianna** on Monday, November 7, 2011 at 2:25pm.

I am sooo clueless please help!

- Math College -
**Steve**, Monday, November 7, 2011 at 6:56pmSince you want at least two sixes, figure the probability of 0 or 1 six, then take the complement:

P(0) = (5/6)^14 * (1/6)^0 * 14!/0!/14!

P(1) = (5/6)^13 * (1/6)^1 * 14!/1!13!

calculate that and subtract it from 1. That's your answer.

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