Posted by **lindsay** on Monday, November 7, 2011 at 1:50pm.

A survey was conducted to measure the number of hours per week adults spend on home

computers. In the survey, the number of hours was normally distributed, with a mean of 8

hours and a standard deviation of 1 hour. A survey participant is randomly selected. Find the

probability that the hours spent on the home computer by the participant are between 5.5 and

9.5 hours per week.

- statistics -
**PsyDAG**, Tuesday, November 8, 2011 at 11:05am
Z = (score-mean)/SD

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to your Z scores.

- statistics -
**Anonymous**, Sunday, March 15, 2015 at 3:34pm
0.3258

- statistics -
**Anonymous**, Friday, October 14, 2016 at 4:38pm
Z-scores: (9.5-8)/1=1.5 and (5.5-8)/1=-2.5. Corresponding probabilities: 94.41%

and 0.62%, so the answer is P=94.41%-0.62%=93.79%

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