Posted by lindsay on Monday, November 7, 2011 at 1:50pm.
A survey was conducted to measure the number of hours per week adults spend on home
computers. In the survey, the number of hours was normally distributed, with a mean of 8
hours and a standard deviation of 1 hour. A survey participant is randomly selected. Find the
probability that the hours spent on the home computer by the participant are between 5.5 and
9.5 hours per week.

statistics  PsyDAG, Tuesday, November 8, 2011 at 11:05am
Z = (scoremean)/SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to your Z scores.

statistics  Anonymous, Sunday, March 15, 2015 at 3:34pm
0.3258

statistics  Anonymous, Friday, October 14, 2016 at 4:38pm
Zscores: (9.58)/1=1.5 and (5.58)/1=2.5. Corresponding probabilities: 94.41%
and 0.62%, so the answer is P=94.41%0.62%=93.79%
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