Posted by **Louisa** on Monday, November 7, 2011 at 11:11am.

What is the area of a regular pentagon with a side length of 9.4 feet and an apothem length of 6.5 feet?

- Geometry -
**denise**, Monday, November 7, 2011 at 2:36pm
asume 11 and 12 are parallel 5 is 83 what is the measure of 7

- Geometry -
**Steve**, Monday, November 7, 2011 at 6:30pm
no sides of a regular pentagon are parallel

5 is not 83

7 is 7

What planet are you calling from?

Divide the pentagon into 5 congruent triangles with base angles of 54°

If s = side length,

the triangles have base = s

then the apothem is h = s/2 tan 54°

The area of the pentagon is 5 * s/2 * s/2 tan 54° = 5s^2*tan54°/4

Note that this is just area = 1/2 * perimeter * apothem

Note: 6.5/4.7 = 1.383 but tan54° = 1.376 so the above dimensions do not fit a regular pentagon.

Ignoring that, however, and using their figures,

a = 5*9.4/2 * 6.5 = 152.75

- Geometry -
**Kiara**, Sunday, February 26, 2012 at 8:06pm
Erica is playing with some regular pentagon tiles and discovers she can made a five pointed star:Explain how she can use angle measures of the pentagons to fink the angle measure of the point of the star

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