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calculous

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A particle moves on the x –axis so that its position at any time is given by x(t) = 2t3 + 1.
a. Find the acceleration of the particle at t = 0.
b. Find the velocity of the particle when its acceleration is 0.
c. Find the total distance traveled by the particle from t = 0 to t = 5.

  • calculous - ,

    x = 3 t^3 + 1

    dx/dt = 9 t^2

    d^2x/dt^2 = 18 t

    so at t = 0 both acceleration and velocity are 0

    velocity is always greater than 0 so the particle never backs up. Therefore all we need is the position at t = 5 minus the position at t = 1
    x(5) = 251
    x(1) = 7
    ------------
    difference = 244

  • calculous - ,

    thank you!!!!!!!!!!! I don't think any of my teachers would deticate some of their time for us:D

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