Posted by Yoona on Monday, November 7, 2011 at 9:07am.
A particle moves on the x –axis so that its position at any time is given by x(t) = 2t3 + 1.
a. Find the acceleration of the particle at t = 0.
b. Find the velocity of the particle when its acceleration is 0.
c. Find the total distance traveled by the particle from t = 0 to t = 5.

calculous  Damon, Monday, November 7, 2011 at 10:39am
x = 3 t^3 + 1
dx/dt = 9 t^2
d^2x/dt^2 = 18 t
so at t = 0 both acceleration and velocity are 0
velocity is always greater than 0 so the particle never backs up. Therefore all we need is the position at t = 5 minus the position at t = 1
x(5) = 251
x(1) = 7

difference = 244

calculous  Yoona, Monday, November 7, 2011 at 12:18pm
thank you!!!!!!!!!!! I don't think any of my teachers would deticate some of their time for us:D
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