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November 28, 2014

November 28, 2014

Posted by **mymi** on Monday, November 7, 2011 at 3:42am.

(a) What is the volume flow rate at the exit?

(b) What is the acceleration at the exit? The length of the nozzle is 2 m.

(c) If the volume flow rate through the nozzle is increased to 7 m3/s, what is the acceleration of the fluid at the exit?

I got the correct answer for a which is 3.27 m^3/s, help me on part b and c please.

- Physics -
**drwls**, Monday, November 7, 2011 at 5:29am(b) and (c) are poorly worded questions. Once the water reaches the exit, acceleration stops. Prior to that, while water is still in the channel,

V*A = b^2*V = constant

= volume flow rate, Q

b is the side length of the square water channel

2 ln b + ln V = 0

(1/V)dV/dt = (1/V)*acceleration

= -2 (db/dt)(1/b)

= -2 (db/dx)*(1/b)*V

acceleration = -V^2*(1/b)*db/dx

To get an answer, you need to know the distance over which the side length b decreases from 0.64 to 044 m.

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