Friday

April 18, 2014

April 18, 2014

Posted by **Yoona** on Monday, November 7, 2011 at 12:09am.

a. Find the zeros of f

b. Write an equation of the line tangent to the graph of f at x = -1

c. Find the x coordinate of the point where the tangent line is parallel to the secant line on the interval [1, 3].

- calculus -
**Damon**, Monday, November 7, 2011 at 1:48amWell, first off, if x=1 we have a zero.

So divide by (x-1) and get

x^2+x-6

factor that

(x-2)(x+3)

so the zeros are at x = 1, 2, -3

At x - -1

y = -1 + 7 + 6 = 12

y' = 3 x^2 - 7 which is -4 at x = -1

so this line goes through (-1,12) and has slope m = -4

You can do the rest

at x = 1, y = 0

at x = 3, y = 27-21+6 = 12

line slope m = 12/2 = 6

where is slope of tangent line = 6?

3x^2 -7 = 6

3 x^2 = 13

x^2 = 13/3

x = sqrt (13/3)

**Related Questions**

Calculus - If a graph of a function is given and they tell you to draw the ...

Calculus - flickr.(dotcom)/photos/77304025@N07/6782789880/ Create a function ...

Calculus - Find the linear approximation L(x) of the given function at a, and ...

Calculus - Given the position function s(t) = t cos t, find the velocity ...

Calculus - Given the function" f(x)=1/4x− 3, find a formula for the ...

calculus - Determine values of a and b that make the given function continuous...

calculus - The function y=f(x) graphed above is assumed to be a vertical shift ...

pre calculus - for the given function f and g, find the specified value of the ...

Calculus (Continuity and Differentiability) - Okay. So I am given a graph of a ...

Calculus, check my answers, please! - Could someone tell me if I'm right, and ...