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November 26, 2014

November 26, 2014

Posted by **Brett** on Sunday, November 6, 2011 at 10:47pm.

f(x)=(x^(3)-8)^(2/3)

Please Show Work

- Calculus -
**Steve**, Monday, November 7, 2011 at 1:09pmJust use the good old chain rule.

f = (x^{3}-8)^{2/3}

f' = 2/3 * (x^{3}-8)^{-1/3}* 3x^{2}

f' = 2x^{2}/(x^{3}-8)^{1/3}

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