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posted by Brett Sunday, November 6, 2011 at 10:47pm.
Differentiate f(x)=(x^(3)-8)^(2/3) Please Show Work
Just use the good old chain rule. f = (x^{3}-8)^{2/3} f' = 2/3 * (x^{3}-8)^{-1/3} * 3x^{2} f' = 2x^{2}/(x^{3}-8)^{1/3}
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