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November 26, 2014

November 26, 2014

Posted by **ed** on Sunday, November 6, 2011 at 10:32pm.

- Physics -
**drwls**, Sunday, November 6, 2011 at 11:10pm(1) The volume of the displaced water is 1.78 kg divided by the density of water, 1000 kg/m^3.

That is 1.78*10^-3 m^3 or 1780 cm^3

(2) The buoyant force (in Newtons) is 1.78 kg * 9.8 m/s^2

(3) How deeply it floats depends upon its position in the water. Is the cylinder axis parallel or perpendicular to the water surface?

Comparing the displaced water volume to the cylinder volume will tell you the fraction that is under water.

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