Posted by rachel on Sunday, November 6, 2011 at 10:27pm.
If the water in the filter is at depth x, with the surface of radius r,
x/r = 4/2 = 2
x = 2r
r = x/2
now, the volume of the water in the cup, plus that in the filter adds up to 10
cone: v = 1/3 pi r^2 x = pi/12 x^3
cup: v = pi r^2 y = 4pi y
pi/12 x^3 + 4pi y = 10
pi/4 x^2 dx/dt + 4pi dy/dt = 0
multiply by 4/pi to simplify a bit:
x^2 dx/dt + 16 dy/dt = 0
You can massage that into whatever form you need.
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