Posted by bec on Sunday, November 6, 2011 at 9:54pm.
suppose a simple pendulum was released from an angle of 58 degrees, with a length of 0.75m and mass of .15kg. what would be the speed of the bob at the bottom of the swing? To what height would the bob get to on the other side. What angle of release would give half the speed of that for 58 degree release angle at the bottom of the swing?

physics  drwls, Sunday, November 6, 2011 at 11:32pm
The bob rises to the same height on the opposite sde.
MgL(1  costheta) + (1/2) M V^2
= M g L[1 cos(thetamax)]
M cancels out.
At the bottom of the swing,
theta = 0 and
V^2 = 2 g L [1cos(thetamax)] = Vmax^2
For half the velocity at bottom,
1  cos(theta)max must be reduced by a factor of 4. Theta becomes 28 degrees.
Answer This Question
Related Questions
 Physics  The length of a simple pendulum is 0.72 m, the pendulum bob has a mass...
 physics  Suppose the simple pendulum shown below were released from an angle ...
 physics  Suppose the simple pendulum shown below were released from an angle of...
 Physics  A simple pendulum, 2.0 m in length, is released from rest when the ...
 Physics  The length of a simple pendulum is 0.58 m, the pendulum bob has a mass...
 physics  ¬Calculate the period of oscillation of a simple pendulum of length 1....
 physics  energy question  A simple pendulum, 2.0 m in length, is released with...
 physicsURGENT  An 85 cm long pendulum with a 0.80 kg bob is released from rest ...
 Physics  A pendulum bob is released from some initial height such that the ...
 introductory to physics  A pendulum bob is released from some initial height ...
More Related Questions