Homework Help: physics

Posted by bec on Sunday, November 6, 2011 at 9:54pm.

suppose a simple pendulum was released from an angle of 58 degrees, with a length of 0.75m and mass of .15kg. what would be the speed of the bob at the bottom of the swing? To what height would the bob get to on the other side. What angle of release would give half the speed of that for 58 degree release angle at the bottom of the swing?

physics - drwls, Sunday, November 6, 2011 at 11:32pm
The bob rises to the same height on the opposite sde.

MgL(1 - costheta) + (1/2) M V^2
= M g L[1 -cos(thetamax)]
M cancels out.
At the bottom of the swing,
theta = 0 and
V^2 = 2 g L [1-cos(thetamax)] = Vmax^2

For half the velocity at bottom,
1 - cos(theta)max must be reduced by a factor of 4. Theta becomes 28 degrees.

Answer this Question

Related Questions

Physics - The length of a simple pendulum is 0.58 m, the pendulum bob has a mass...
Physics - You pull a simple pendulum of length L to the side through an angle of...
physics - The length of a simple pendulum is 0.79m and the mass of the particle ...
Physics - The length of a simple pendulum is 0.72 m, the pendulum bob has a mass...
Osciallations - You pull a simple pendulum of length 0.237m to the side through ...
Physics - Suppose that a simple pendulum consists of a small 66.0 g bob at the ...
Physics - A simple pendulum of the length 0.350 m starts from rest at a max ...
Physics - A simple pendulum, 2.0 m in length, is released from rest when the ...
physics - A simple pendulum has a length of 1.5 m and is pulled a distance y = 0...
physics (shm) - Suppose that a simple pendulum consists of a small 55.0 g bob at...

For Further Reading

First Name:
School Subject:
Answer: