Thursday

April 17, 2014

April 17, 2014

Posted by **Kate** on Sunday, November 6, 2011 at 9:19pm.

- trig -
**Steve**, Monday, November 7, 2011 at 11:48amUsing the identity cos(a-b) = cos a cos b + sin a sin b

cos(θ-50) = cosθcos50 + sinθsin50

= .64cosθ + .77sinθ

so,

19cos(θ-50) = 19(.64cosθ + .77sinθ)

= 12.16cosθ + 14.63sinθ

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