Posted by **Adam** on Sunday, November 6, 2011 at 8:26pm.

Water is flowing freely from the bottom of a conical tank which is 12 feet deep and 6 feet in radius at the

top. If the water is flowing at a rate of 2 cubic feet per hour, at what rate is the depth of the water in the

tank going down when the depth is 3 feet.

- calculus -
**Steve**, Monday, November 7, 2011 at 11:39am
When the water is x feet deep, and the surface has radius r, then by similar triangles,

x/r = 12/6

x = 2r

r = x/2

So, since the volume of water

v = 1/3 pi r^2 x

= 1/12 pi x^3

dv/dt = pi/4 x^2 dx/dt

-2 = pi/4 (9) dx/dt

dx/dt = -8/(9pi) = -.28 ft^3/hr

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