Posted by Iki on Sunday, November 6, 2011 at 7:56pm.
Fp = 415N. = Force parallel to the ramp
a. W = Fp*d = 415 * 2 = 830 Joules.
b. Wc = mg = 66kg * 9.8N/ikg = 647N. =
Weight of crate.
Work = Fc*h = 647 * 1 = 647 Joules.
Related Questions
physics - A crate slides down a ramp inclined at 26.0° from the horizontal. ...
Physics - A 45 kg crate is placed on an inclined ramp. When the angle the ramp ...
Physics - A 31.0 kg crate, initially at rest, slides down a ramp 2.6 m long and ...
Physics - A 31.0 kg crate, initially at rest, slides down a ramp 2.6 m long and ...
Physics-Help Please!!! - A 31.0 kg crate, initially at rest, slides down a ramp...
Physics - A 19 kg crate is placed on an inclined ramp. When the angle the ramp ...
physics - A 15 kg crate is held with a rope at the top of a metal ramp that has ...
Physics - A crate of mass 29 kg is pushed up a ramp by a person as shown in the ...
Physics - A 32 kg crate is placed on an inclined ramp. When the angle the ramp ...
Physics - A 32 kg crate is placed on an inclined ramp. When the angle the ramp ...
For Further Reading