Post a New Question

College Physics

posted by on .

A child plays on a bungee cord and oscillates with a certain frequency f. An adult with a mass that is 16 times greater than that of the child then uses the same bungee cord. What is the ratio of the frequency with the adult to the frequency with the child?

I tried to answer this question using:
Freq(adult)/Freq(child)= [(1)/(2pie)] * sqrt (k/(value-for-how-many-times-greater-adult-is-than-child)m)/ [(1)/(2pie)] * sqrt (k/m)

...BUT I got lost because I don't know what to do with the k constants... any ideas??

  • College Physics - ,

    what is sqrtk/sqrtk? answer: it divides out.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question