Homework Help: College Physics

Posted by Anon on Sunday, November 6, 2011 at 7:32pm.

A child plays on a bungee cord and oscillates with a certain frequency f. An adult with a mass that is 16 times greater than that of the child then uses the same bungee cord. What is the ratio of the frequency with the adult to the frequency with the child?

I tried to answer this question using:
Freq(adult)/Freq(child)= [(1)/(2pie)] * sqrt (k/(value-for-how-many-times-greater-adult-is-than-child)m)/ [(1)/(2pie)] * sqrt (k/m)

...BUT I got lost because I don't know what to do with the k constants... any ideas??

College Physics - bobpursley, Sunday, November 6, 2011 at 7:38pm
what is sqrtk/sqrtk? answer: it divides out.

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