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December 18, 2014

December 18, 2014

Posted by **anon** on Sunday, November 6, 2011 at 7:28pm.

- statistics -
**PsyDAG**, Monday, November 7, 2011 at 12:08amZ = (mean1 - mean2)/SEm

Z = (65.25-64.37)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to the Z score.

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