Posted by **John** on Sunday, November 6, 2011 at 7:07pm.

sgr2 sinD cosD=sinD

- math -
**Steve**, Monday, November 7, 2011 at 11:13am
If you're trying to solve

sqrt(2) sinD cosD = sinD

sinD(sqrt(2) cosD - 1) = 0

sinD = 0 means that D=0 + k*pi for any integer k will work.

cosD = 1/√2 means that D=2k*pi ± pi/4 will also work.

- math -
**John**, Thursday, November 10, 2011 at 11:57am
So:

47

137

227

317

Do I need to add +360n?

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