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Posted by on Sunday, November 6, 2011 at 7:07pm.

sgr2 sinD cosD=sinD

  • math - , Monday, November 7, 2011 at 11:13am

    If you're trying to solve

    sqrt(2) sinD cosD = sinD

    sinD(sqrt(2) cosD - 1) = 0

    sinD = 0 means that D=0 + k*pi for any integer k will work.

    cosD = 1/√2 means that D=2k*pi ± pi/4 will also work.

  • math - , Thursday, November 10, 2011 at 11:57am

    So:

    47
    137
    227
    317

    Do I need to add +360n?

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