math
posted by
John
.
sgr2 sinD cosD=sinD

math 
Steve
If you're trying to solve
sqrt(2) sinD cosD = sinD
sinD(sqrt(2) cosD  1) = 0
sinD = 0 means that D=0 + k*pi for any integer k will work.
cosD = 1/√2 means that D=2k*pi ± pi/4 will also work.

math 
John
So:
47
137
227
317
Do I need to add +360n?