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March 24, 2017

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A certain calculus student hit Mrs. Evans in the head with a snowball. If the snowball is melting at the rate of 10 cubic feet per minute, at what rate is the radius of the snowball changing when the snowball is 1 foot in radius?

  • Calculus - ,

    That is a pretty big snowball !

    V = (4/3) pi r^3

    dV/dt = (4/3) pi 3 r^2 dr/dt

    10 = 4 pi r^2 dr/dt
    since r = 1
    dr/dt = 10/(4 pi)

    note : using common sense we knew that. The rate of change of the volume is the surface area 4 pi r^2 times the rate of radius change

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