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February 27, 2015

February 27, 2015

Posted by **Kokos** on Sunday, November 6, 2011 at 3:27pm.

- Calculus -
**Steve**, Monday, November 7, 2011 at 5:42amIf we place the origin (0,0) at the base of the 12' stake, then the 28' stake has its base at (30,0).

If the length of wire used is

L = sqrt(x^2 + 12^2) + sqrt((x-30)^2 + 28^2)

= sqrt(x^2 + 144) + sqrt(x^2 - 60x + 1684)

dL/dx = x/(sqrt(x^2 + 144) + (x-30)/sqrt(x^2 - 60x + 1684)

dL/dx = 0 when x=9

so, place the stake between the poles, 9' from the short pole, and 21' from the tall pole.

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