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September 30, 2014

September 30, 2014

Posted by **jj snoke** on Sunday, November 6, 2011 at 3:19pm.

- calculus -
**Steve**, Monday, November 7, 2011 at 4:55amv = 1/3 pi r^2 h

r^2 + h^2 = 25

v = 1/3 pi (25-h^2)h = 1/3 pi (25h - h^3)

a max/min occurs when dv/dh = 0:

25 - 3h^2 = 0

h = 5/√3

r = 5√2/√3

It's a max because v'' < 0

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