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July 29, 2014

July 29, 2014

Posted by **don** on Sunday, November 6, 2011 at 11:53am.

interval 0 to 2 pi

exact answers and formula for the general solution as well as the specific solutions.

Sorry Steve, missed it last night.

- MATH C30 -
**Steve**, Sunday, November 6, 2011 at 7:52pmIf I'm reading it right, we have

cos tan + √3 cos - √3/2 tan - 3/2 = 0

rearrange terms a bit to get

tan(cos - √3/2) + √3(cos - √3/2) = 0

(tan + √3)(cos - √3/2) = 0

tan x = -√3 --> x = 2pi/3 or 4pi/3

x = (2k+1)*pi +/- pi/3

cos x = √3/2 --> x = pi/6 or 11pi/6

x = k*2pi +/- pi/6

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