Posted by don on Sunday, November 6, 2011 at 11:53am.
If I'm reading it right, we have
cos tan + √3 cos - √3/2 tan - 3/2 = 0
rearrange terms a bit to get
tan(cos - √3/2) + √3(cos - √3/2) = 0
(tan + √3)(cos - √3/2) = 0
tan x = -√3 --> x = 2pi/3 or 4pi/3
x = (2k+1)*pi +/- pi/3
cos x = √3/2 --> x = pi/6 or 11pi/6
x = k*2pi +/- pi/6
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