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algebra

posted by on .

Find value of
log (base 8)log (base 2) log (base 3)log (base 3) (27)^3


I endedup with 1.000063462 which was wrong

  • algebra - ,

    If you want to use a calculator to evaluate the above expression, you will need to understand the above expression is evaluated from right to left, so appropriate sets of parentheses must be inserted.

    In fact, the above expression can be evaluated mentally to a simple fraction.

    log (base 8)log (base 2) log (base 3)log (base 3) (27)^3
    should be written as follows (square brackets have been inserted):
    log (base 8) [log (base 2) [ log (base 3) [ log (base 3) (27)^3 ] ] ]
    Start evaluating from the innermost set of brackets outwards.

  • algebra - ,

    zero.

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