Friday

February 27, 2015

February 27, 2015

Posted by **Skylar** on Saturday, November 5, 2011 at 10:18pm.

Please use the work equation

- Math -
**MathMate**, Sunday, November 6, 2011 at 12:20amThe large one can fill in x hours,

then the small one in (x+6) hours.

During each hour, working together, the two hoses can fill 1/x+1/(x+6) of the pool, or (2x+6)/(x(x+6)).

Since using both hoses, it fills the pool in 4 hours, each hour fills 1/4 of the pool, therefore:

1/x + 1/(x+6) = 1/4

(2x+6)/(x(x+6)) = 1/4

4(2x+6)=x(x+6)

x² -2x -24 = 0

Solve for x (reject the negative root).

The large one will fill in x hours alone, and the small one, x+6 hours.

**Answer this Question**

**Related Questions**

Algebra - Two hoses are connected to a swimming pool. Working together, they can...

Math - The Timuga swimming pool, of Manila City has two pumps it uses to fill ...

algebra - A garden hose can fill a swimming pool in 7 days, and a larger hose ...

c - A hose can fill a swimming pool in 4 hours. Another hose needs 9 more hours ...

Math - Four hoses are filling a pool. The first hose alone would fill the pool ...

algebra - Pump A can fill a swimming pool in 6 hours and pump B can fill the ...

math - Hose A can fill a pool in 4 hours. Hose B can fill the pool in 2 hours.If...

math - If pump A and pump B work together, they can fill a pool in 4 hours. Pump...

math - Three water pipes are used to fill a swimming pool. The 1st pipe alone ...

college algebra - a garden hose can fill a pool in 3 days and a longer one can ...