Determine the acceleration of the marble from the straight line equation you calculated in question 2.

So the equation i found in Q2 was y=9.84x+6.79

How do i figure out acceleration from this? please help!

If y is displacement, and x is time...I have no idea what your equation is...

then acceleration is zero. Notice the change in position is directly dependent on x, meaning constant velocity.

y is velocity and x is time.

thank you :)

To determine the acceleration from the given equation, we need to recognize that the given equation represents a straight line in the form y = mx + b, where m is the slope of the line. In this case, the slope of the line is 9.84.

In physics, acceleration (a) is the rate of change of velocity (v) with respect to time (t). Since the given equation does not directly represent velocity or time, we need to make some additional assumptions.

If we assume that the equation represents the position (y) of a marble as a function of time (x), then we can interpret the equation as follows:

The coefficient of x (9.84 in this case) represents the velocity of the marble. The positive sign indicates that the marble is moving in the positive direction.

So, the acceleration can be obtained by taking the derivative of the velocity equation (or the slope of the velocity equation):

a = dv/dt = d(9.84x)/dt = 9.84 * dx/dt

However, since we do not have a time variable explicitly mentioned in the equation, we cannot directly find the acceleration from the given equation alone.