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Chemistry

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Propane, C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would need to provide 369 kJ of heat.
C3H8 (g) + 5O2 (g) --> 3CO2 (g)+ 4H2O (g) ; Delta H = -2043kJ

  • Chemistry - ,

    2,043 kJ x (grams C3H8/44) = 369 kJ
    Solve for grams.

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