Homework Help: Chemistry

Posted by Anonymous on Saturday, November 5, 2011 at 3:30pm.

Propane, C3H8, is a common fuel gas. Use the following to calculate the grams of propane you would need to provide 369 kJ of heat.
C3H8 (g) + 5O2 (g) --> 3CO2 (g)+ 4H2O (g) ; Delta H = -2043kJ

Chemistry - DrBob222, Saturday, November 5, 2011 at 5:00pm
2,043 kJ x (grams C3H8/44) = 369 kJ
Solve for grams.

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