pleast help me work this prob
lead is a toxic meatal that affects the central nervous system. a Pb-contaminated water sample contains 0.0011% Pb by mass. What vilume of the water in milliliters contains 115g of Pb? (assume that the density of the solution is 1.0g/ml
masstotal=masswater+masslead
percentlead=masslead/(masswater+masslead)*100
.0011=11500/(masswater+115)
masswater=11500/.0011 - 115
that is mass water in grams.
volume water=densitywater*masswater
.
i think I need help setting this up. Not looking for the answer just want to understand it. Than you
To solve this problem, we need to use the given information and apply some calculations. Here's how we can do it step by step:
Step 1: Calculate the mass of the water present in the Pb-contaminated water sample.
- Since we know that the Pb content is 0.0011% by mass, this means that 0.0011% of the sample's mass is Pb.
- Therefore, the mass of Pb in the sample can be calculated by multiplying the total mass of the sample by 0.0011.
- So, the mass of Pb in the sample is (0.0011/100) * mass of the sample.
Given that 115g of Pb is present, we can set up an equation to solve for the mass of the sample:
(0.0011/100) * mass of the sample = 115g
To find the mass of the sample, we can rearrange the equation:
mass of the sample = (115g * 100) / 0.0011
Step 2: Calculate the volume of the water.
- We're given that the density of the solution is 1.0g/ml.
- Density is defined as mass per unit volume.
- Therefore, the volume of the water can be calculated by dividing the mass of the sample by the density.
volume of the water = mass of the sample / density
Finally, we can substitute the calculated values into the equation to find the volume of water in milliliters.
Let's do the math:
Step 1:
mass of the sample = (115g * 100) / 0.0011
mass of the sample = 1,045,454g
Step 2:
volume of the water = mass of the sample / density
volume of the water = 1,045,454g / 1.0g/ml
volume of the water ≈ 1,045,454 ml
Therefore, the volume of water in milliliters that contains 115g of Pb is approximately 1,045,454 ml.